Throw exception from user code in SpringFailOnTimeout even if a timeout occurs
Issue: SPR-16717
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committed by
Sam Brannen
parent
697d2e326f
commit
3c34a1cb8c
@@ -0,0 +1,45 @@
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package org.springframework.test.context.junit4.spr16716;
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import org.junit.Test;
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import org.junit.runner.RunWith;
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import org.junit.runners.model.Statement;
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import org.mockito.Mock;
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import org.mockito.junit.MockitoJUnitRunner;
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import org.mockito.stubbing.Answer;
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import org.springframework.test.context.junit4.statements.SpringFailOnTimeout;
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import java.util.concurrent.TimeUnit;
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import java.util.concurrent.TimeoutException;
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import static org.mockito.Mockito.doAnswer;
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import static org.mockito.Mockito.doThrow;
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/**
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* Validate SpringFailOnTimeout contract
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* <a href="https://jira.spring.io/browse/SPR-16716" target="_blank">SPR-16716</a>.
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*
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* @author Igor Suhorukov
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* @since 5.0.6
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*/
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@RunWith(MockitoJUnitRunner.class)
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public class SpringFailOnTimeoutExceptionTest {
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@Mock
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private Statement statement;
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@Test(expected = IllegalArgumentException.class)
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public void validateOriginalExceptionFromEvaluateMethod() throws Throwable {
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IllegalArgumentException expectedException = new IllegalArgumentException();
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doThrow(expectedException).when(statement).evaluate();
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new SpringFailOnTimeout(statement, TimeUnit.SECONDS.toMillis(1)).evaluate();
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}
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@Test(expected = TimeoutException.class)
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public void validateTimeoutException() throws Throwable {
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doAnswer((Answer<Void>) invocation -> {
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TimeUnit.MILLISECONDS.sleep(50);
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return null;
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}).when(statement).evaluate();
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new SpringFailOnTimeout(statement, TimeUnit.MILLISECONDS.toMillis(1)).evaluate();
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}
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}
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