Correctly format class name in default package
Closes gh-27247
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@@ -44,6 +44,7 @@ import org.springframework.util.Assert;
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import org.springframework.util.ClassUtils;
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import org.springframework.util.LinkedMultiValueMap;
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import org.springframework.util.MultiValueMap;
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import org.springframework.util.StringUtils;
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import org.springframework.web.cors.CorsConfiguration;
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import org.springframework.web.cors.CorsUtils;
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import org.springframework.web.method.HandlerMethod;
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@@ -301,9 +302,12 @@ public abstract class AbstractHandlerMethodMapping<T> extends AbstractHandlerMap
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}
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private String formatMappings(Class<?> userType, Map<Method, T> methods) {
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String formattedType = Arrays.stream(ClassUtils.getPackageName(userType).split("\\."))
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.map(p -> p.substring(0, 1))
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.collect(Collectors.joining(".", "", "." + userType.getSimpleName()));
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String packageName = ClassUtils.getPackageName(userType);
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String formattedType = (StringUtils.hasText(packageName) ?
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Arrays.stream(packageName.split("\\."))
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.map(packageSegment -> packageSegment.substring(0, 1))
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.collect(Collectors.joining(".", "", "." + userType.getSimpleName())) :
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userType.getSimpleName());
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Function<Method, String> methodFormatter = method -> Arrays.stream(method.getParameterTypes())
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.map(Class::getSimpleName)
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.collect(Collectors.joining(",", "(", ")"));
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