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Handle fully qualified type names in resource from JMX bean

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This commit is contained in:
BoykoAlex
2018-02-16 16:07:01 -05:00
parent ffe2ef5b80
commit 6745fb4925
1 changed files with 8 additions and 1 deletions
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9
headless-services/commons/commons-boot/src/main/java/org/springframework/ide/vscode/boot/java/utils/SpringResource.java
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@@ -1,5 +1,5 @@
/*******************************************************************************
* Copyright (c) 2017 Pivotal, Inc.
* Copyright (c) 2017, 2018 Pivotal, Inc.
* All rights reserved. This program and the accompanying materials
* are made available under the terms of the Eclipse Public License v1.0
* which accompanies this distribution, and is available at
@@ -36,6 +36,9 @@ public class SpringResource {
private IJavaProject project;
private static final Pattern BRACKETS = Pattern.compile("\\[[^\\]]*\\]");
private static final String ID_PATTERN = "\\p{javaJavaIdentifierStart}\\p{javaJavaIdentifierPart}*";
private static final String REGEX_FQCN = ID_PATTERN + "(\\." + ID_PATTERN + ")*";
public SpringResource(SourceLinks sourceLinks, String toParse, IJavaProject project) {
this.sourceLinks = sourceLinks;
@@ -44,6 +47,10 @@ public class SpringResource {
if (matcher.find()) {
type = toParse.substring(0, matcher.start()).trim();
path = toParse.substring(matcher.start()+1, matcher.end()-1);
} else if (Pattern.matches(REGEX_FQCN, toParse)) {
// Resource is fully qualified Java type name
type = CLASS_PATH_RESOURCE;
path = toParse.replace('.','/') + SourceLinks.CLASS;
} else {
path = toParse;
}