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Use Servlet 3.0 Part instead of Spring MultipartFile

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So that it can handle multi-part requests that do not have a
file name.

Fixes gh-1067
This commit is contained in:
Dave Syer
2016-06-06 14:32:43 +01:00
parent 1c7c96a245
commit b6fa67c49f
1 changed files with 12 additions and 7 deletions
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19
spring-cloud-netflix-core/src/main/java/org/springframework/cloud/netflix/zuul/filters/pre/FormBodyWrapperFilter.java
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@@ -27,8 +27,11 @@ import java.util.Set;
import javax.servlet.ServletInputStream;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.Part;
import org.apache.commons.lang3.StringUtils;
import org.springframework.core.io.InputStreamResource;
import org.springframework.core.io.Resource;
import org.springframework.http.HttpEntity;
import org.springframework.http.HttpHeaders;
import org.springframework.http.HttpOutputMessage;
@@ -181,15 +184,17 @@ public class FormBodyWrapperFilter extends ZuulFilter {
MultipartRequest multi = (MultipartRequest) this.request;
for (Entry<String, List<MultipartFile>> parts : multi
.getMultiFileMap().entrySet()) {
for (MultipartFile part : parts.getValue()) {
MultipartFile file = part;
for (Part file : this.request.getParts()) {
HttpHeaders headers = new HttpHeaders();
headers.setContentDispositionFormData(file.getName(),
file.getOriginalFilename());
headers.setContentType(
MediaType.valueOf(file.getContentType()));
HttpEntity<byte[]> entity = new HttpEntity<byte[]>(
file.getBytes(), headers);
file.getSubmittedFileName());
if (file.getContentType() != null) {
headers.setContentType(
MediaType.valueOf(file.getContentType()));
}
HttpEntity<Resource> entity = new HttpEntity<Resource>(
new InputStreamResource(file.getInputStream()),
headers);
builder.add(parts.getKey(), entity);
}
}